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115 Verses 147


usmc1974

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I am not a rocket scientist so I need to know or try and understand, IPSC power factors. A 115 going 1300 has 431 pounds energy but don't make major. A 147 going 1125 makes major but only has 413 pounds of energy. Am I missing something?Thanks usmc1974

PF=VxW/1000

ENERGY=VxVxW/450240

115x1300/1000=149.500

PF=149.50

115x1300x1300/450240=431.658

ftlb energy=431.658

147x1125/1000=165.375

PF=165.375

147x1125x1125/450240=413.217

ftlb energy=413.217

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Nope. PF does not equal KE, it's a measure of momentum. The reason Open shooters shoot light bullets is to get the powder gas to work the comp. PD shooters like 147's for the low powder charges and lower KE.

Search around.. there's a ton here on "is recoil related to KE or PF?", and various technical discussions thereof one way and the other.

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Power factor was never designed to class ammo as to energy. It measures momentum. It came about to group handguns with similar amounts of recoil, so that lighter recoiling guns (for instance, BHPs and S&W M39s) would be scored together (peripheral hits get fewer points), and heavier recoiling guns - in those times, Colt Government Models in .45 ACP - would get more points for less-than-center hits. In those days, with the carry ammo that was commonly available, it was a decent approximation of their relative effectiveness for self-defense.

Edited by revchuck
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