lndshrk Posted September 22, 2004 Share Posted September 22, 2004 EXACTLY what is the formula to get from time, scored hits, misses, procedurals, no-shoot hits, and misses to MATCH POINTS? Link to comment Share on other sites More sharing options...
Kingman Posted September 22, 2004 Share Posted September 22, 2004 Time is Obvious Your points are the point value for the target minus penalties. divide points by time that is your hit factor. Your hit factor is divided by the high hit factor for the course. Your percentage is multiplied by max points for the stage. that ponit value is your points for a stage. Link to comment Share on other sites More sharing options...
reneet Posted September 22, 2004 Share Posted September 22, 2004 Covered previously Check here. http://www.brianenos.com/forums/index.php?...l=uspsa+scoring Link to comment Share on other sites More sharing options...
lndshrk Posted September 22, 2004 Author Share Posted September 22, 2004 I read all of the above and still am confused. Here goes from match shot Sunday: Total Points (222 hits x 5) - 1110 Points Down - 60 Penalties - 30 Time - 298.62 HF -3.42 How did I get a MATCH PTS = 795.2949 ????? I'm sure it is simple, but it ain't easy . . . still elludes me! Link to comment Share on other sites More sharing options...
SmittyFL Posted September 22, 2004 Share Posted September 22, 2004 You have to do it on a stage by stage basis, not the whole match. Whoever scores the best in division on any given stage gets the maximum amount of points available on that stage. Whether they actually shot all the available points or not. Then everybody else in that division is scored off of them on a curve. You need to figure your points for each stage, then add them up for your total match points. I'll try to give an example: El Presidente Maximum points available = 60 Lets say a guy named Rob L. shoots 56 points in 4.5 seconds. 56 / 4.5 = a hit factor of 12.4444 You shoot 54 points in 7 seconds. 54 / 7.0 = a hit factor of 7.7143 Your factor divided by the highest factor for the stage (rob) 7.7143 / 12.4444 = 61.99% So you shot 61.99% of the best shooter that day. He automatically gets all the available stage points (60) so you would get 61.99% of 60 points or: 37.194 stage points. So for that given stage at that match you would get 37.194 Match Points. You do that for every stage at the match then add them up for your total match points. Hope this helps Link to comment Share on other sites More sharing options...
bgary Posted September 22, 2004 Share Posted September 22, 2004 You can't get there from there. Each stage is calculated separately, and the sum of all the *stage* points you collect is your match-point total. Lets say that Stage 1 is a 115-point course. -- you shoot it in 12.55 seconds, with a score of 91 points -- your resulting hitfactor is (91 / 13.55) = 6.7159 -- the TOP shooter gets 111 points in 7.11 seconds -- his resulting hitfactor is (111 / 9.11) = 15.6118 So, your *percentage* on that stage is (6.7159 / 15.6118) = 43.0181% Now... what that means is that the stage winner gets 100% of the available points on the stage, and you get 43.0181% of those points Your *stage* points for that stage are (115 * .430181) = 49.4708 points Add together your *stage* points for each stage, to get the total number of *match* points. Bruce Link to comment Share on other sites More sharing options...
lndshrk Posted September 22, 2004 Author Share Posted September 22, 2004 Thanks, now I understand why I couldn't figure it out with my numbers alone! Link to comment Share on other sites More sharing options...
Eye Cutter Posted September 26, 2004 Share Posted September 26, 2004 isn't it that in IPSC's scoring system, the competitor who got the highest hit factor gets the actual points he shot for that stage instead of the max. stage points and everybody else's score is a percentage of their hit factors relative to the stage winner's hit factor? is my understanding of the scoring system correct? ex. Stage 1: 80 pts competitor A: score=70 pts, time 8sec, HF= 8.75 competitor B: score=76 pts, time 12 sec, HF= 6.33 competitor C: score=74 pts, time 10 sec, HF= 7.40 Stage 1 1. A 70pts, 8sec, HF 8.75, Score 70 pts, 100% 2. C 74pts, 10sec, HF 7.40 Score 59.2 pts (7.40/8.75)(70), 84.57% 3. B 76pts, 12sec, HF 6.33 Score 50.64 pts (6.33/8.75)(70), 72.34% this avoids the previous scoring system's caveat of placing a premium on speed over accuracy. correct? Link to comment Share on other sites More sharing options...
Vince Pinto Posted September 26, 2004 Share Posted September 26, 2004 isn't it that in IPSC's scoring system, the competitor who got the highest hit factor gets the actual points he shot for that stage instead of the max. stage points and everybody else's score is a percentage of their hit factors relative to the stage winner's hit factor? No. If there are 100 points available, and the guy with the highest Hit Factor only gets 90 points, he is still given the maximum 100 points, with all other competitors ranked proportionally below him (see Rule 9.2.2.1 and 9.2.3.1). This is called "stage factoring". The only time you get actual points shot without "stage factoring" is with Fixed Time stages (see Rule 9.2.4.1). Link to comment Share on other sites More sharing options...
Eye Cutter Posted September 26, 2004 Share Posted September 26, 2004 thanks for clearing that up for me, Pareng Vince! so in my previous example, the correct results would be: Stage 1 80 pts Total Rank, Name, Score, Time, HF, Stage Pts, % 1. A 70pts, 8sec, 70 pts, HF 8.75, 80 pts, 100% 2. C 74pts, 10sec, 76 pts, HF 7.40, 67.656 pts 84.57% (7.40/8.75) 3. B 76pts, 12sec, 74 pts, HF 6.33, 57.872 pts, 72.34% thanks! Link to comment Share on other sites More sharing options...
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